This article explain detailed procedure to calculate numerical value of a capacitor's capacitance to be connected with an Inductive load like induction motor to improve power factor from one value to other given value.
Please note that current power factor is 0.5 it indicates that motor is induction motor or an inductive load is connected to the system.Data extracted from above problem : -
Improving power factor does not change active power consumed in the appliance.Since the voltage also same so only current will be changed after power factor improvement. Hence only total current will be changed but active component will be same i.e. 25 Amp.
Ic = V/Xc = 2*pi*f*C*VC = 451 * 10-6 F
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